Question

Find the area of a triangle having perimeter 32cm one side of its side is equal to 11cm and difference of the other two is 5cm

Answer 1

Answer:

One side of triangle =11cm

Other sides =32-11 = 21

Now lets give the sides name,

side A=11cm

side B=?

side C=?

Step-by-step explanation:

we know that B+C=21 -(eq1)

Given that difference of the other two sides is 5cm

That means B is 5 more than C or C is 5 more than B

We assume B is 5cm more than C

i.e B=C+5

Now substitute the value of B in (eq 1)

B+C=21

(C+5)+C=21

2C+5=21

2C=21-5

2C=16

C=8cm

Now substitute the value of C in (eq 1)

B+C=21

B+8=21

B=21-8

B=13cm

HOPE IT WAS HELPFUL