Question

find the area of a triangle having perimeter 32cm one side of its side is equal to 11 cm and difference of the other two is 5 cm

Answer 1

let the sides be a,b and c
therefore
a+b+c=32
a=11
11+b+c=32
b+c=21
and
b-c=5

on adding the equation

2b=26
b=13

and thus c=8

therefore area =√s(s-a)(s-b)(s-c)

=s=11+13+8/2
=32/2
=16

=√16*5*3*8
=√80*24
=√1920
43.8