Question

find the area of a triangle having side 13 cm , 14 cm , 15 cm

give me the correct answer​

Answer 1

Given sides of triangle
a=13,b=14,c=15

Semi-perimeter s=
2
1
​
(a+b+c)=
2
1
​
(13+14+15)=21

Area, A =
s(s−a)(s−b)(s−c)
​

A=
21(21−13)(21−14)(21−15)
​

A=84 cm
2

Answer 2

Answer:

Given sides of triangle

Given sides of trianglea=13,b=14,c=15

Given sides of trianglea=13,b=14,c=15Semi-perimeter s= 21 cm

(a+b+c)/2=21 cm

(13+14+15)/2=21

=21Area, A =√s(s−a)(s−b)(s−c)

s(s−a)(s−b)(s−c)

s(s−a)(s−b)(s−c)

s(s−a)(s−b)(s−c) A=√21(21−13)(21−14)(21−15)

21(21−13)(21−14)(21−15)

21(21−13)(21−14)(21−15)

21(21−13)(21−14)(21−15) A=84 cm²