Question

Find the area of a triangle having the points A(1 1 1),B (1 2 3),C(2 3 1)as it vertices.

Answer 1

Answer:

∆=3/2squnits.

Step-by-step explanation:

∆=1/2|1 1 1|

1 23

2 3 1

=1/2|1(2-9)-1(1-6)+1(3-4)|=3/2sq unit.