find the area of a triangle having two sides = 10 cm and the triangle is inscribes in a cirle of radius 10 cm
Answers
Answered by
1
Solution:
r=a+b-c/2
10=10+10-c/2
10×2/20=-c
-c=1cm
c=-1cm
r=a+b-c/2
10=10+10-c/2
10×2/20=-c
-c=1cm
c=-1cm
singhasjokkumap49bce:
sorry i didnt get it
Answered by
0
r=a+b-c/2
a=10, b=10 ,r=10
10=10+10-c/2
20=20-c
c=0
area of triangle=1/2*base*altitude
area of triangle=1/2*10*10
=50
may it will help you
a=10, b=10 ,r=10
10=10+10-c/2
20=20-c
c=0
area of triangle=1/2*base*altitude
area of triangle=1/2*10*10
=50
may it will help you
no the ans is wrong
then what it's the answer
Similar questions