Find the area of a triangle having vertices as x(4, 3), y( 6, 3) and z(0, 3). Justify your answer.
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Area of the triangle is
=1/2( 4(3-3)+6(3-3)+0(3-3)
=1/2 x 0
=0
As the area is 0 the points X,Y,Z are colinear.
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