Math, asked by yani5228, 1 year ago

Find the area of a triangle having vertices as x(4, – 3), y(– 6, – 3) and z(0, – 3). Justify your answer.

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Answered by serdan2114
1

Area of a triangle

 =  \frac{1}{2} ( x_{1} (y_{2} - y_{3}) +  x_{2}( y_{3} -  y_{1}) +  x_{3}( y_{1} -  y_{2})

  • the three points are collinear that is they lie on the same line . therefore the area is zero
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