Question

Find the area of a triangle if its base and height are 12 cm and 5 cm respectively.​

Answer 1

• Given

• Base of a triangle = 12 cm
• Height of a triangle = 5 cm

• To find

• Area of triangle

• Solution

$\underline{\boxed{\sf{Area~of~triangle~= \dfrac{1}{2} \times base \times height}}}$

Substitute the given values.

⇛ $\sf{\dfrac{1}{2} \times 12 \times 5}$

⇛ 30 cm²

$\underline{\boxed{\sf{Area~of~triangle~= 30~cm^2}}}$

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Know MorE -

There three types of triangle -

• Equilateral triangle
• Isosceles triangle
• Scalene triangle 

• Equilateral triangle -

• In this all three sides are equal.

Area of equilateral triangle -

• $\sf{\dfrac{\sqrt{3}}{4}a^2}$

Perimeter of equilateral triangle -

• 3a

where,

a = side of triangle

• Isosceles  triangle -

• In this two sides of triangle are equal.

Area of isosceles triangle -

• $\sf{\dfrac{1}{2} \times base \times height}$

Perimeter of isosceles triangle -

• 2a + b

• Scalene triangle -

• In this no side is equal.

Area of scalene triangle -

• Heron's formula = $\sf{\sqrt{s(s - a)(s - b)(s - c)}}$

Perimeter of scalene triangle -

• Perimeter = Sum of all three sides