Question

Find the area of a triangle if its sides are 21 cm 17 cm and 10cm

Answer 1

Answer:

By heron's formula...

a=21cm

b=17cm

c=10cm

$s = \frac{21 + 17 + 10}{2} \\ = \frac{48}{2} \\ = 24$

(s-a) = 24-21= 3

(s-b)= 24-17=7

(s-c)= 24-10=14

Area of Triangle

$\sqrt{s(s - a)(s - b)(s - c)} \\ \sqrt{24 \times 3 \times 7 \times 14} \\ \sqrt{2 \times 2 \times 2 \times 3 \times 3 \times 7 \times 2 \times 7} \\ 2 \times 2 \times 3 \times 7 \\ 84cm {}^{2}$

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