Question

Find the area of a triangle if its sides are. (i)52cm , 60cm and 56cm
Please give me answer​

Answer 1

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Answer 2

$\sf\red{Answer:-}$

$\sf{Area\: is\: 1344cm^2}$

$\sf \green{Given:-}$

$\sf Sides\: of\: triangle\: are :-\\ \sf 52cm \\ \sf 60 cm \\ \sf 56cm$

$\sf \purple{To \: find:-}$

$\sf Area\: of\: triangle$

$\sf \pink{Solution :-}$

$\sf Here, we \: find \: the \: area \: by \: using \: herons \: formula$

$\sf Area = \sqrt{s(s-a)(s-b)(s-c)}$

$\sf where ,$

$\sf s= semi\: perimeter \\ \sf a , b, c \: are \: sides\: of\: triangle$

$\sf Firstly , \: we\: find \: the \: semi \: perimeter \: of \: triangle$

$\sf s = \dfrac{a+b+c}{2}$

$\sf s= \dfrac{52+60+56}{2}$

$\sf s= \dfrac{168}{2}$

$\sf s= 84cm$

$\sf So, \: semi\:perimeter \:is \:84 cm$

$\sf Substituting \: the \: values \: in \:formula$

$\sf s= 84 cm \\ \sf a = 52 cm \\ \sf b = 60cm \\ \sf c = 56 cm$

$\sf Area = \sqrt{s(s-a)(s-b)(s-c)}$

$\sf Area = \sqrt{84(84-52)(84-60)(84-56)}$

$\sf Area = \sqrt{84(32)(24)(28)}$

$\sf Area = \sqrt{18,06,336}$

$\sf Area = 1344 cm^2$

$\sf So, \: area \: of \: triangle \: formed\: by \: those\: sides \: are \:1344cm^2$

Note :-

Kindly refer the attachment in order to find the square root for 18,06,336 .