find the area of a triangle if its two sides are 18 cm and 10 cm and the perimeter is 42 CM
Answers
Answered by
6
perimeter of triangle=P=42 cm
sides of triangle a=18cm, b=10cm & c=?
P=a+b+c
42=18+10+c
c=42-28
c=14cm
Semiperimeter, S= P/2= 42/2=21cm
Area = √21(21-18)(21-10)(21-14)
= √21*3*11*7
=√7*7*3*3*11
=7*3√11
=21√11 sqcm
hope it is useful
sides of triangle a=18cm, b=10cm & c=?
P=a+b+c
42=18+10+c
c=42-28
c=14cm
Semiperimeter, S= P/2= 42/2=21cm
Area = √21(21-18)(21-10)(21-14)
= √21*3*11*7
=√7*7*3*3*11
=7*3√11
=21√11 sqcm
hope it is useful
Similar questions