Find the area of a triangle (in cm square)whose two equal sides are of 5cm and third side is 4cm. *
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Answer:
Area = 2√21 cm²
Step-by-step explanation:
side 'a' of the triangle = 5 cm
base 'b' of the triangle = 4 cm
hence, height (h) of the triangle = √a²-(b/2)²
h = √5²-(4/2)² = √25-4 = √21
hence, area of the triangle = 1/2 × b × h
= 1/2 × 4 × √21
= 2√21 cm²
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