Find the area of a triangle of side 6cm , 8 cm and 10 cm.
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Looking at the length of the sides notice that 6^2 + 8^2 = 36 + 64 = 100 = 10^2. This is a right triangle with perpendicular sides of length 6 and 8 cm. The area of the triangle is (1/2)*6*8 = 24 cm^2.
The area can also be derived using Heron's theorem. The area is given by where s is the semi-perimeter equal to a = 6, b = 8 and c = 10.
The area of the triangle is equal to= 24 cm^2.
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