Question

find the area of a triangle of sides 4cm, 5cm and 3cm​

Answer 1

Step-by-step explanation:

s=4+5+3/2

s=6

area=√s(s-a)(s-b)(s-c)

√6*2*1*3

area =6cm²

Answer 2

Answer:

the length of the sides are a=4,b=5,c=3

therefore,

s= a+b+c/2= 4+5+3/2=6cm

we use the formula,

∆=√s(s-a)(s-b)(s-c)

=√6(6-4)(6-5)(6-3) sq. cm

=√6×2×1×3sq.cm

=6 sq.cm