find the area of a triangle of sides 4cm, 5cm and 3cm
Answers
Answered by
1
Step-by-step explanation:
s=4+5+3/2
s=6
area=√s(s-a)(s-b)(s-c)
√6*2*1*3
area =6cm²
Answered by
0
Answer:
the length of the sides are a=4,b=5,c=3
therefore,
s= a+b+c/2= 4+5+3/2=6cm
we use the formula,
∆=√s(s-a)(s-b)(s-c)
=√6(6-4)(6-5)(6-3) sq. cm
=√6×2×1×3sq.cm
=6 sq.cm
Similar questions