Question

find the area of a triangle.sides are 3cm,4cm,5cm by the formula √s(s-a)(s-b)(s-c)
Answer is 6çm².!!.​

Answer 1

Answer:

$\large 6 \ cm^2$

Step-by-step explanation:

Given :

Sides of triangle are 3 cm , 4 cm and 5 cm.

We have to find its Area by Henoa ' s formula.

$\large \text{Area of traingle =\sqrt{s(s-a)(s-b)(s-c)} }$

Where s = semiperimeter and a , b and c are sides.

$\large s=\dfrac{a+b+c}{2}\\\\\\\large s=\dfrac{3+4+5}{2}\\\\\\\large s=\dfrac{12}{2}\\\\\\\large s=6 \ cm$

Now putting values in formula we get

$\large \text{Area of traingle =\sqrt{s(s-a)(s-b)(s-c)} }\\\\\\\large \text{Area of traingle =\sqrt{6(6-3)(6-4)(6-5)} }\\\\\\\large \text{Area of traingle =\sqrt{6(3)(2)(1)} \ cm^2 }\\\\\\\large \text{Area of traingle =\sqrt{6\times6} \ cm^2 }\\\\\\\large \text{Area of traingle = 6 \ cm^2 }$

Thus we get answer.