Find the area of a triangle, the radius of whose circumcircle is 3 cm and the length of the altitude drawn from the opposite vertex to the hypotenuse is 2 cm
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Since the triangle has a hypotenuse, it is a right angled triangle.
In right angled triangle, circum radius is half the hypotenuse (because hypotenuse is the diameter of circumcircle.)
So hypotenuse = 3×2 = 6cm
Altitude from opposite vertex to hypotenuse = 2cm
So assuming hypotenuse as base,
base = b = 6cm
altitude = h = 2 cm
area = 1/2 bh = 1/2 × 6 × 2 = 6 cm^2
Area of triangle is 6 cm^2.
In right angled triangle, circum radius is half the hypotenuse (because hypotenuse is the diameter of circumcircle.)
So hypotenuse = 3×2 = 6cm
Altitude from opposite vertex to hypotenuse = 2cm
So assuming hypotenuse as base,
base = b = 6cm
altitude = h = 2 cm
area = 1/2 bh = 1/2 × 6 × 2 = 6 cm^2
Area of triangle is 6 cm^2.
kvnmurty:
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9
Since the triangle has a hypotenuse, it is a right angled triangle.
In right angled triangle, circum radius is half the hypotenuse (because hypotenuse is the diameter of circumcircle.)
So hypotenuse = 3×2 = 6cm
Altitude from opposite vertex to hypotenuse = 2cm
So assuming hypotenuse as base,
base = b = 6cm
altitude = h = 2 cm
area = 1/2 bh = 1/2 × 6 × 2 = 6 cm².
Area of triangle is 6 cm².
HOPE SO IT WILL HELP.....
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