Math, asked by kambojsinghabhi8248, 1 year ago

Find the area of a triangle, the radius of whose circumcircle is 3 cm and the length of the altitude drawn from the opposite vertex to the hypotenuse is 2 cm

Answers

Answered by TPS
24
Since the triangle has a hypotenuse, it is a right angled triangle.

In right angled triangle, circum radius is half the hypotenuse (because hypotenuse is the diameter of circumcircle.)

So hypotenuse = 3×2 = 6cm

Altitude from opposite vertex to hypotenuse = 2cm

So assuming hypotenuse as base,

base = b = 6cm

altitude = h = 2 cm

area = 1/2 bh = 1/2 × 6 × 2 = 6 cm^2

Area of triangle is 6 cm^2.

kvnmurty: Good
Answered by BrainlyFlash156
9

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Since the triangle has a hypotenuse, it is a right angled triangle.

In right angled triangle, circum radius is half the hypotenuse (because hypotenuse is the diameter of circumcircle.)

So hypotenuse = 3×2 = 6cm

Altitude from opposite vertex to hypotenuse = 2cm

So assuming hypotenuse as base,

base = b = 6cm

altitude = h = 2 cm

area = 1/2 bh = 1/2 × 6 × 2 = 6 cm².

Area of triangle is 6 cm².

HOPE SO IT WILL HELP.....

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