find the area of a triangle two side of which are 18cm and 10cm perimeter is 42cm.
Answers
Answered by
2
Answer:
69.65 cm² is the area of the given triangle.
Answered by
5
Answer:
21√11 cm^2
Step-by-step explanation:
sides : 18 cm,10cm, 42-(10+18) =14cm
s,semiperimeter = 42/2=21
area=√s(s-a)(s-b)(s-c)
= √21(21-18)(21-10)(21-14)
=√21*3*11*7
=21√11 cm^2
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