Question

Find the area of a triangle , two side of whose are 4 cm and 5cm and perimeter is 12 cm.
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Answer 1

Answer:

hii friend

here is your answer

sol: perimeter=12

let three sides be a, b, c

a+ b+ c=12

4+5+c=12

c=3

hence the three sides are 4,5,3

Area of the triangle=$\sqrt{s(s-a)(s-b)(s-c)}$              [s=(a+b+c)/2]

                                 =$\sqrt{6(6-4)(6-5)(6-3)}$

                                 =√6x2x1x3

                                 =6cm²

hope this helps you

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Answer 2

Answer:

Step-by-step explanation:

Look we could solve the question using herons formula

So herons formula says that :

$\sqrt{s (s-a)(s-b)(s-c)$

where s = semi perimeter which is equal to side a + side b + side c / 2

= 12/2 = 6 cm

Side c = 12 - ( 5+4)

          =  3 cm

using herons formula we get

$\sqrt{6 ( 6-4) ( 6-5) ( 6 - 3)$

= whole root 6 * 2 * 1 * 3

= root 36

= 6 cm sq .

Hope this helps.... Took a lot time writing it... Also pls mark as brainliest