Question

find the area of a triangle two sides of which 8 cm & 10 cm and its perimeter is 42 cm​

Answer 1

Answer:

according to Pythagoras triplet

10square=8square+the missing number

100=64+the missing number

100-64=36√=6

so, area =√24×18×16×8

=√2×2×3×2×2×2×2×2×3×2×2×2

=96 is the answer