Question

Find the area of a triangle two sides of which 8 cm and 11 cm and the perimeter is 32 cm?​

Answer 1

Answer:

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Answer 2

Answer:

since the sum of all three sides of a triangle is its perimiter

• a + b + c = 32 cm

8 + 11 + c = 32

19 + c = 32

c = 32 - 19

c = 13

now by using herons formula which is √s (s -a )(s-b)(s-c) where s is semi perimiter of a triangle

semi - perimeter of this triangle = 32/2

= 16

area of the triangle = √ 16 (16-8)(16-11)(16-13)

= √(16 x 8 x 5 x 3 )

= √( 2 x 2x 2 x 2 x 2 x 2 x2 x 5 x 3 )

= 2 x 2 x2 x √( 2 x 5 x 3 )

= 8√30 cm*2

HOPE THIS HEPLS !!