Find the area of a triangle two sides of which are 12cm and 8 cm and the perimeter is 32 cm.
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Answered by
2
Answer:
perimeter = 12 + 8 + X
32 = 12+ 8 + X
32-20 = X
12 = X
area of a triangle = 1/2*BH
=1/2*12*8
=48
Answered by
2
Step-by-step explanation:
Perimeter of triangle=AB+BC+AC
32cm=20cm+AB
AB=12cm
Therefore , It is an isosceles triangle
Consider AD as altitude
(AD)^2+(BD)^2=(AB)^2
(AD)^2+(4cm)^2=(12cm)^2
(AD)^2=144cm^2-16cm^2
(AD)^2=128cm^2
AD=√2×8×8
AD=8√2cm
Area of triangle=(1/2)×(8cm)×(8√2cm)
=32√2cm^2
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