Question

find the area of a triangle , two sides of which are 13cm and 14cm and the perimeter is 42 cm ​

Answer 1

Answer:

Area=84

Step-by-step explanation:

The two sides of triangle are a=13,b=14

Given perimeter =42

a+b+c=42

13+14+c=42

c=42-27=15

Area of triangle=

$\sqrt{s(s - a)(s - b)(s - c)}$

where

$s =( a + b + c) \div 2$

s=(13+14+15)/2

=42/2

=21

Area of triangle=

$\sqrt{21(21 - 13)(21 - 14)(21 - 15)}$

A =

$\sqrt{21(8)(7)(6)}$

A=√(7²×3²×4²)

=7×3×4

=84