Find the area of a triangle, two sides of which are 14cm and 11 cm and the perimeter is 42 cm
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Step-by-step explanation:
1ST SIDE = 14Cm
2nd side = 11 cm
3 rd side = 42 - ( 14+ 11)
= 42 - 25
=17cm
area of triangle = √ s ( s- a) ( s-b) ( s-c)
where , s = a + b+ c / 2
s= 14+ 11+ 17/ 2
= 21
√ 21× 7 × 10 × 4
√ 7×3× 7× 5× 2 × 2× 2
7 × 2 √ 3× 5 × 2
14 √ 30 cm2 ans.
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