Question

find the area of a triangle two sides of which are 16cm and 10cm and the perimeter is 40 cm

Answer 1

Hey friend, Harish here.

Here is your answer:

Given that,

1) Two side of a triangle are 16 & 10cm.

2) The perimeter = 40 cm.

To find,

The area of the triangle .

Solution,

Let a , b, c be the sides of the triangle.

Where a = 10, b = 16 , c = ?

The unknown side =  Perimeter - (a+b)

                              =  40 - 26

                              = 14cm

We know that,

$Area\ of\ triangle= \sqrt{s(s-a)(s-b)(s-c)}$

Here , S =  1/2 × Perimeter = 20 .


Then,

$Area = \sqrt{20(20-10)(20-16)(20-14)}$

⇒ $\sqrt{20 \times 10 \times 4\times 6}= \sqrt{10^{2} \times 2^{2}\times 2^{2}\times 3} = 2\times 10\times 2 \sqrt{3} = 40\sqrt{3}$

Therefore area is 40√3 cm.
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Hope my answer is helpful to you.

Answer 2

Hey !!

Your answer is in the attachment..⬆⬆

Hope it helps you..

Thanks ^-^