Math, asked by Abanishkhal, 1 year ago

Find the area of a triangle two sides of which are 16cm and 10cm and the perimeter is 40cm ​

Answers

Answered by stylishsojal
0

40=16+10+y

y=14 cm

the third side is of 14cm

Answered by SwastiJain07
2

perimter =  \: sum \: of \: all \: sides \\  \\ 40 = 16 + 10 + x \\  \\ 40 = 26 + x \\  \\ 40 - 26 = x \\  \\ x = 14 \: cm

so..area \:  =  \frac{1}{2}  \times b \times h

we will use Pythagoras theoram for finding height....

p {}^{2}  + b ^{2}  = h {}^{2}

 {p}^{2}  +  {14}^{2}  =  {16}^{2}  \\  \\ p {}^{2}  + 196 = 256 \\  \\ p {}^{2}  = 256 - 196 \\  \\ p {}^{2}  = 60 \\  \sqrt{60}  = 7.74 \: cm

area =  \frac{1}{2}  \times 14 \times 7.74 \\  \\ area = 54.18 \:   {cm}^{2}

hope it helped you☺☺

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