find the area of a triangle two sides of which are 18 and 10 cm and the perimeter is 42
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semi perimeter = s = 42/2 = 21 cm
third side = 42 - 10 - 18 = 14 cm
area of triangle = root(s(s-a)(s-b)(s-c))
= root(21 x 3 x 11 x 7)
= 21 √11 cm
third side = 42 - 10 - 18 = 14 cm
area of triangle = root(s(s-a)(s-b)(s-c))
= root(21 x 3 x 11 x 7)
= 21 √11 cm
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