find the area of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42 CM
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Answer:
the third side is 14 cm as 18+10+x = 42 so the area will be 1/2 bh = 1/2 x 10 x 18 = 90
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3rd Side- 42-28 = 14
periimeter- 42
semi perimeter- 42/2=21
Area v21x3x11x7=v4851=69.65cm2
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