Math, asked by bijoysonar, 11 months ago

find the area of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42 CM​

Answers

Answered by charan02032006
5

Answer:

the third side is 14 cm as 18+10+x = 42 so the area will be 1/2 bh = 1/2 x 10 x 18 = 90

Answered by haridasan85
2

3rd Side- 42-28 = 14

periimeter- 42

semi perimeter- 42/2=21

Area v21x3x11x7=v4851=69.65cm2

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