Question

find the area of a triangle two sides of which are 18 cm and 10 cm ànd the perimeter is 42 cm

who did not know the answer so please don't tell wrong ans please right send me​

Answer 1

Answer:

$21 \sqrt{11 }$ sq. cm

Answer 2

Answer:

a=18cm b=10cm

perimeter of triangle =a+b+c=18+10+c

42=18+10+c

42=28+c

c=14cm

semi perimeter =s=a+b+c/2 =18+10+14/2=42/2=21cm

area of triangle =√s(s-a)(s-b)(s-c)

=√21(21-18)(21-10)(21-14)

=√21×3×11×7

=21√11 cm²=69.64cm²

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