Question

find the area of a triangle two sides of which are 18 cm and 14cm and the perimeter is 42cm​

Answer 1

Answer:

Perimeter of triangle = a+b+c

42 = 18+14+c

42 = 32+c

42-32 = c

10 = c

Half perimeter of triangle (s) = a+b+c/2

= 18+14+10/2

=42/2

=21

Area of triangle = √s(s-a)(s-b)(s-c)

√21(21-18)(21-14)(21-10)

√21×3×7×11

√4851

√441×11

21√11 cm²

Hence,Area of triangle=21√11cm²

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