Question

find the area of a triangle two sides of which are 18 cm and 14cm and the perimeter is 42cm​

Answer 1

Answer:

$Area of triangle s(s−a)(9−b)(s−0)​ Here, s is the semi- perimeter,and a,b,c are the sides of the triangleGiven a=18 cm, b=10 cmand perimeter =42 cmsemi- perimeters= 2perimeter​ = 242​ s=21cm.Area of triangle ∴c=42−(18+10)cm =14 cm∴ Area of triangle= 21.(21−18)(21−10)(21−14)​ = 21.3.7.11​ cm 2 = 3×7×3×7×11​ cm 2 = (3×7) 2 ×11​ cm 2 =21 11​ cm 2 ∴ Thus, the required area of the triangle is 21 11 ​ cm 2​$

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