Question

Find the area of a triangle two sides of which are 18 com and 10 cm the perimeter is 42 cm.​

Answer 1

Answer:

3rd side =42-28=14

S=21

Heron's formula=root of s.s-a.s-b.s-c

=root of (21×3×11×7)

=21×√11

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Answer 2

Answer:

21√11cm²

Step-by-step explanation:

Perimeter= Side + Side + Side

Take third side as x.

42= 18 + 10 + x

x= 42 - 28

x= 14cm

Hence, third side is equal to 14 cm.

Now, using Heron's formula:

S=(18 + 10 + 14)÷2

S=42÷2

S=21.

Now,

        Area = √21×3×11×7

                 = √7×3×3×11×7

                 = 7×3√11

                 = 21√11cm².