find the area of a triangle two sides of which are 18cm and 10 cm and the perimeter is 42 cm by heron formula
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S=42/2
PERIMETER-(a+b)=c
42-(10+18)=c
c=14
ARea =√21(21-18)(21-14)(21-10)
=√21×3×11×7
21√11
PERIMETER-(a+b)=c
42-(10+18)=c
c=14
ARea =√21(21-18)(21-14)(21-10)
=√21×3×11×7
21√11
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