Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is 42cm?
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let, a=18cm,b=10cm,s=42/2=21cm
in a triangle,
a+b+c=perimeter
18+10+c=42cm
28+c=42
c=42-28=14cm
area of a triangle=√s(s-a)(s-b)(s-c)=√21(21-18)(21-10)(21-14)
=√21×3×11×7=√4851=7√99cm²
I hope that u will completely understand it...
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