Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is 42cm.
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Hello❤!!
Side A=18 cm
Side B=10 cm
Side C= 14 cm
=14+18+10/2=42/2
=21
So here,
√s(s-a)(s-b)(s-c)
√3×7 √11
21√11cm^2
Answered by
6
Answer:
21 root 11
Step-by-step explanation:
Refer the picture
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