Math, asked by manisha925, 11 months ago

Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is 42cm.​

Answers

Answered by Anonymous
0

Hello❤!!

Side A=18 cm

Side B=10 cm

Side C= 14 cm

=14+18+10/2=42/2

=21

So here,

√s(s-a)(s-b)(s-c)

√3×7 √11

21√11cm^2

Answered by vsnamritha1204
6

Answer:

21 root 11

Step-by-step explanation:

Refer the picture

HOPE IT HELPS

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