Question

Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is 42cm.​

Answer 1

Hi mate

Here is your answer

Hope it will help❤✌

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Perimeter of triangle = sum of all sides

42cm = 18cm + 10cm + x cm

x cm = 42- 28 cm

x = 14 cm

Area of triangle:

Semi perimeter, s = perimeter/2

= 42/2 =21 cm

a = 10 cm

b=18 cm

c = 14 cm

s-a = 21 -10 =11 cm

s-b= 21-18 =3 cm

s-c = 21- 14 = 7cm

Area = √[s * (s-a) *(s-b) * (s-c)]

= √[21 * 11 * 3 * 7]

=√[4851]

= 69.65 sq. cm (approx)

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