Question

find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is 42cm​

Answer 1

Answer:

Area of triangle = 90 cm²

Third side of triangle = 56 cm

Answer 2

Step-by-step explanation:

42=18+10+s

42=28+s

s=42-28

s=14

semi perimeter=42/2=21

area of =

$\sqrt{s \:(s - a)(s - b)(s - c)}$

$\sqrt{21(21 - 18)(21 - 10)(21 - 14)}$

$\sqrt{7 \times 3(3)(11)(7)}$

$\sqrt[3 \times 7]{11}$

$\sqrt[21]{11}$