Math, asked by shivamsingh1q2w3e, 1 month ago

Find the area of a triangle two sides of

which are 18cm and 10cm and the

perimeter is 42cm.​

Answers

Answered by vasimvj27
1

Answer:

42 = 18 + 10 + x

42 - 18 - 10 = x

42 - 28

16 = x

Answered by evamariapatrice
0

Answer:

Area = 126 cm²

Step-by-step explanation:

Perimeter = 42 cm.

Let's take the missing length as x.

Perimeter = 18 + 10 + x

42 = 18 + 10 + x

Let's transpose the given values

x + 10 = 42 - 18

x + 10 = 24

x = 24 - 10

x = 14

The missing side is 14.

Area = 1/2 × B × H

Let's take base as 14 cm.

And take height as 18 cm

= 1/2 × 14 × 18

= 1/2 × 252 = 126²

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