Question

Find the area of a triangle two sides of which are 24 cm and 16 cm and the perimeter is 54 cm

Answer 1

107.62cm²

is the right answer

Answer 2

Answer:

Step-by-step explanation:

first side of the triangle = a = 24 cm

second side of the triangle = b = 16 cm

third side of the triangle = c

a + b = 24 + 16 = 40 cm

perimeter of triangle = a + b + c + = 54 cm

hence,

c = 54 - 40 = 14 cm

also,

s = $\frac{a + b + c}{2} = \frac{54}{2} = 27$

now, by the heron's formula

area of the triangle = A =

A = $\sqrt{27(27-24)(27-16)(27-14)}$

A = $\sqrt{27 (3)(11)(13)}$

A = $\sqrt{11583}$

A = 107.624346688