Question

Find the area of a triangle, two sides of which are 8 cm and 11 cm and the perimeter is 32 cm

Answer 1

Answer:

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,8+11=32

11+8

19

32÷2

2

19+2

21

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Answer 2

Answer:

A=s(s﹣a)(s﹣b)(s﹣c)

P=a+b+c

s=a+b+c

2

Solving forA

A=1

4﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab﹣4(Pb)2+8Pa2b+8Pab2=1

4·﹣324+4·323·8+4·323·11﹣4·(32·8)2﹣12·322·8·11﹣4·(32·11)2+8·32·82·11+8·32·8·112≈43.8178cm²