Question

Find the area of a triangle, two sides of which are 8 cm and 11 cm and the perimeter is 32

cm.​

Answer 1

Answer:

Area of a triangle = 43.8178cm²

Answer 2

☘️ Solution :

Here we have perimeter of triangle = 32 cm, a = 8 cm and b = 11 cm.

Third side c = 32 cm - (8 + 11)cm = 13 cm

So, 2s = 32, i.e., s = 16 cm,

s - a = (16 - 8) cm = 8 cm,

s - b = (16 - 11) cm = 5 cm,

s - c = (16 - 13) cm = 3 cm.

Therefore, area of the triangle

$\sf \: = \sqrt{s(s - a) \: (s - a) \: (s - c) } \\ \\ \sf \: = \sqrt{16 \times 8 \times 5 \times 3} \: cm {}^{2} \\ \\ \sf \: = \large \purple{ 8 \sqrt{30} \: cm {}^{2} }$

☘️ Answer :

• 8√30 cm²