Math, asked by sanikagaund, 7 hours ago

Find the area of a triangle, two sides of which are 8 cm and 12 cm and the perimeter is 38 cm

A. 16√3 cm²

B. 64 cm²

C. √1463 cm²

D. 24√3 cm²​

Answers

Answered by 0hyung0
0
The correct answer is c part
Attachments:
Answered by rsroy83
0

Answer:

Step-by-step explanation:

Let a,b,c be the sides of the given triangle and 2s be its perimeter such that

a=8 cm, b=11 cm and 2s=32 cm

Now, a+b+c=2s

8+11+c=32

c=13

Therefore,

s−a=16−8=8,s−b=16−11=5,s−c=16−13=3

Hence, area of given triangle =  

s(s−a)(s−b)(s−c)

 

=  

16×8×5×3

=8  

30

 cm  

2

Similar questions