Question

Find the area of a triangle, two sides of which are 8 cm and 11cm and the perimeter is 32 cm

Answer 1

Area of triangle =√s(s-a)(s-b)(s-c)
in given triangle
a=8
b=11
c=?
s=16
perimeter=16×2
=32=8+11+c
32=19+c
c=32-19
c=13
area=√16(16-8)(16-11)(16-13)
√16(8)(5)(3)
4×4×2×2×2×5×3
4×2√2×5×3
8√30cm^2 I

I hope this will help you

Answer 2

$2s = a + b + c \\ 2s = 32 \\ a = 8 \\ b = 11 \\ = > c = 13 \\ area = \sqrt{s(s - a)(s - b)(s - c)} \\ = \sqrt{16 \times 8 \times 5 \times 3} \\ = \sqrt{1920} \\ = 43.82$
hope it helps