Question

find the area of a triangle two sides of which are 8cm 11 cm and perimeter 32cm?



anyone Jinda here?​

Answer 1

Answer:

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Answer 2

Let a,b,c be the sides of the given triangle and 2s be its perimeter such that

a=8 cm, b=11 cm and 2s=32 cm

Now, a+b+c=2s

8+11+c=32

c=13

Therefore,

s−a = 16−8

=8,

s−b = 16−11

=5,

s−c =1 6−13

=3

Hence, area of given triangle = 

$\sqrt{s(s−a)(s−b)(s−c)</p><p>}$

=

$\sqrt{ 16×8×5×3}$

Answer "

$8 \sqrt{30 {cm}^{2} }$

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