Find the area of a Triangle, two sides of which are 8cm and 11cm and the perimeter is 32cm
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Answer:
Perimeter = 32 cm
sides are:- 8cm , 11cm, x
8cm + 11 cm + x = 32 cm
19cm +x = 32cm
X = 32-19 = 14cm
Area= √s(s-a)(s-b)(s-c) {Heron's Formula}
Semi-perimeter = 32/2 = 16 cm
Area = √16(16-8)(16-11)(16-14)
Area = √16(8)(5)(2)
Area = √8*2*8*5*2
Area = 16√5 sq.cm
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