Question

find the area of a triangle ,two sides of which are 8cm and 11cm and the perimeter is 32cm

Answer 1

Hey ! here is your answer.


I HOPE IT WILL HELP YOU

Answer 2

Hey friend,
Here is the answer:

Given,
The 1st side = 8 cm
The 2nd side = 11 cm
The perimeter = 32 cm

Perimeter = a + b + c
32 = 8 + 11 + c
32 = 19 + c
c = 32 - 19
c =13

$semi - perimeter = \frac{a + b + c}{2} \\ = s = \frac{8 + 11 + 13}{2} \\ = s = \frac{32}{2} \\ = s = 16$

Area of triangle ( according to Heron's Formula) = √s (s - a)(s - b)( s - c)

= √ 16 (16 - 8)( 16 - 11)(16 - 13)

= √ 16 × 8 × 5 × 3

= √1920

$area \: of \: triangle = 43.817 {cm}^{2}$

Hope my answer would be helpful to you!!!

And if helpful, then please mark as brainliest.

@Mahak24

Thanks...
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