Question

Find The Area Of A Triangle Using Heron's Formula Whose Sides Are 3cm, 4cm and 5cm.

Answer 1

HELLO DEAR,

we know that:-
the semi perimeter of a triangle is

s = (a+b+c)/2

where

a=3cm,b=4cm ,c=5cm

$s = \frac{3 + 4 + 5}{2} \\ \\ = > s = \frac{12}{2} = 6cm$

we also know that the:-

by HERON'S FORMULA

AREA of triangle =
$\sqrt{s(s - a)(s - b)(s - c)} \\ \\ = > \sqrt{6(6 - 3)(6 - 4)(6 - 5)} \\ \\ = > \sqrt{6 \times 3 \times 2 \times 1} \\ \\ = > \sqrt{6 \times 6} = 6cm^{2}$

I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Given sides are 3cm, 4cm and 5cm.

We know that semi-perimeter of a triangle s = a + b + c/2

                                                                          = 3 + 4 + 5/2

                                                                          = 12/2

                                                                          = 6cm.



Using Heron's formula, we know that Area of the triangle:

$= \sqrt{s(s-a)(s-b)(s-c)}$

$= \sqrt{6(6 - 3)(6 - 4)(6 - 5)}$

$= \sqrt{6(3)(2)(1)}$

$= \sqrt{36}$

$6 cm^2.$


Therefore the area of triangle = 6cm^2.


Hope this helps!