Find the area of a triangle wen 2 sides are 24cm n 10 cm and the perimeter of the triangle is 62 cm
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let the unknown side be x.
area of perimeter is sum of all sides.
therefore,
24+10+x=62
34+x=62
x=62-34
x=28.
area= 1/2 bh
= 1/2 x 28 x 10
= 140 sq.cm
area of perimeter is sum of all sides.
therefore,
24+10+x=62
34+x=62
x=62-34
x=28.
area= 1/2 bh
= 1/2 x 28 x 10
= 140 sq.cm
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