Question

find the area of a triangle who's side are 8,11 and 13 cm by heron's formula​

Answer 1

Answer:Correct option is

B

8  

30

​  

cm  

2

 

Let third side be x

Perimeter =8+11+x

19+x=32

x=13

S=  

2

32

​  

=16

Heron's formula

A=  

S(S−A)(S−B)(S−C)

​  

 

=  

16(16−8)(16−11)(16−13)

​  

 

=  

16×8×5×3

​  

 

=8  

30

​  

 cm  

2

Explanation:

Answer 2

Explanation:

a=8

b=11

c=13

s=(a+b+c) /2

s=(8+11+13)/2

s=32/2

s=16

heron's formula

A=√s(s-a)(s-b)(s-c)

A=√16(16-8)(16-11)(16-13)

A=√16×8×5×3

A=√4×4×4×2×5×3

A=4×2√30

A=8√30

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