find the area of a triangle who's side are 8,11 and 13 cm by heron's formula
Answers
Answered by
2
Answer:Correct option is
B
8
30
cm
2
Let third side be x
Perimeter =8+11+x
19+x=32
x=13
S=
2
32
=16
Heron's formula
A=
S(S−A)(S−B)(S−C)
=
16(16−8)(16−11)(16−13)
=
16×8×5×3
=8
30
cm
2
Explanation:
Answered by
8
Explanation:
a=8
b=11
c=13
s=(a+b+c) /2
s=(8+11+13)/2
s=32/2
s=16
heron's formula
A=√s(s-a)(s-b)(s-c)
A=√16(16-8)(16-11)(16-13)
A=√16×8×5×3
A=√4×4×4×2×5×3
A=4×2√30
A=8√30
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