find the area of a triangle whose all sides are equal and sum of the 3 sides is equal to 12cm
Answers
Answered by
2
Let all equal sides be a.
a+a+a=12
3a=12
a=12/3
a=4
Now apply the formula
Area = root3/4×a square
=root 3 / 4 × 4 ×4
= root 3 × 4
= 1.73 ×4 (substituting value of rootas 1.73)
= 6.92 (answer)
chetankatigar:
thank you so much
Answered by
0
Soln,
Given that, sum of all three sides= 12 cm
Therefore,
a+b+c= 12 cm
3a = 12 cm (all sides are equal)
a = 4
Hence, area (equilateral triangle)=√3a^2/4
= √3×4×4/4
=4√3 cm^2
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