find the area of a triangle whose all sides are equal and sum of the 3 sides is equal to 12cm....
.......... please give answer now I'm in class
Answers
Answered by
15
There Is A Triangle Whose All Sides Are Equal And Some Of The Sides Is Equal To 12cm . We Need To Find
The Area of The Triangle..
So Let's Move To Solution ...
According To The Question It's Given That The All Sides Of The Triangle Are Equal and Their Sum Is Equal To
12 centimetre.
Now To Find It's Area Of Triangle Follow The Simple Steps ....
So Let The Length Of Side of Triangle = X
That Is ...
Now Taking 3 To RHS We Have ....
Therefore We Have ....
Hence The Length Of The Sides Are ...
We Have A Formula Called The That Is ....
⏺️ Where " S " Is The Half Of The Perimeter ... And a , b & c Are the sides of Triangle
So Here Perimeter = 12cm. ( Given )
Therefore Half of Perimeter = 12/2 = 6cm
Hence
So Now The sides a,b & c We Have
⏺️As It's Given That All Sides Are Equal
Now Putting Values Of a, b & c And " S " In Formula We Have ....
That Is ---
Now We Can split 6 As 2 × 3 So We Have...
That Is Equal To ....
BrainlyKing5:
is this answer CORRECT
Answered by
5
Given: Sides of the triangle are equal and its perimeter adds up to 12cm.
To find: The area.
Answer:
Heron's Formula: √s(s - a)(s - b)(s - c)
Since all the sides are equal, let a, b and c be x.
x + x + x = 12cm
3x = 12cm
x = 12/3
x = 4cm
a + b + c/2 = Semi - Perimeter (s)
4 + 4 + 4/2 = 12/2 = 6cm
s - a = 6 - 4 = 2cm
s - b = 6 - 4 = 2cm
s - c = 6 - 4 = 2cm
Area of the triangle = √s(s - a)(s - b)(s - c)
= √6*2*2*2
= √2*3*2*2*2
= 2*2√3
= 4√3cm^2
Hope it helps :)
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